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40n^2-64n=0
a = 40; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·40·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*40}=\frac{0}{80} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*40}=\frac{128}{80} =1+3/5 $
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